Answer:
0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 3 cm and a standard deviation of 0.04 cm.
This means that 
What is the probability that a bolt has a length greater than 2.96 cm?
This is 1 subtracted by the p-value of Z when X = 2.96. So



has a p-value of 0.1587.
1 - 0.1587 = 0.8413
0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.
Answer:x=1.2
Step-by-step explanation:
3x+2.5=6.1
3x=6.1-2.5
3x=3.6
x=1.2
Using the graph, it is found that 976 passengers had carry-on luggage that weighed less than 20 lb.
<h3>Graph:</h3>
The graph is not given in this problem, but an internet search indicates that the information it contains is as follows:
- 120 passengers carry luggage of 4 lb or less.
- 222 passengers carry luggage between 5 lb and 9 lb.
- 378 passengers carry luggage between 10 lb and 14 lb.
- 256 passengers carry luggage between 15 lb and 19 lb.
- 90 passengers carry luggage between 20 lb and 24 lb.
- 40 passengers carry luggage between 25 lb or more.
Hence, the number of passengers with luggage below 20 lb is:

976 passengers had carry-on luggage that weighed less than 20 lb.
A similar problem, also involving the use of graph, is given at brainly.com/question/25836450