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Evgen [1.6K]
4 years ago
10

What is 6 over 21 in simplest form

Mathematics
2 answers:
Mrac [35]4 years ago
8 0

6/21

Divide the numerator and denominator by using 3.

6/3=2

21/3=7

Answer: 6/21=2/7

Naya [18.7K]4 years ago
7 0

Answer:

2 over 7

Step-by-step explanation:

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The functions have complex roots from the image are

Functions (b) and (d). This is further explained below.

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2 years ago
Select all values of x that make the inequality true -x+6&gt; 10 true .
Rufina [12.5K]

Answer:

<em>C. -4.01</em>

<em>H. -7</em>

Step-by-step explanation:

<u>Solving inequalities:</u>

We have a set of numbers to verify which ones of them make the below inequality true

-x+6>10

Rearrange

-10+6>x

Operating

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Flipping

x

The set of solutions contains every number less than -4

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C. -4.01

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4 0
3 years ago
Read 2 more answers
vic and ben's ages are in the ratio of 3:4. if vic is 12 years old and 3 months old how old is ben in years and months??
posledela
Converting their ages to months:
12*12=144months + 3 months
=147 months
Now, 3 is equivalent to 147 months;
4 will be equivalent to;
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= 196 months
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4 0
3 years ago
Giving away POINTS Tell me your favorite color!
Aleksandr-060686 [28]

Answer:

mint green

Step-by-step explanation:

brainliest?

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2 years ago
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Please help cause I don’t know how to do this
zalisa [80]

Answer:

  4 GB

Step-by-step explanation:

Let "g" represent the number of gigabytes of data used. Then the phone bill is computed as ...

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Aurora's bill is 113, so we can put that value into the equation and solve for g.

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  4 = g . . . . . . . . . divide both sides of the equation by 12

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_____

You can also use your mathematical reasoning to solve this problem. The total bill consists of two charges: a fixed charge of 65 and a charge that depends on data. If you subtract the fixed charge from the bill, you find that the charge that depends on data is 113-65 = 48.

The data charge is 12 times the number of gigabytes. The data charge on the bill is 48, which is 12 times 4. Then the number of gigabytes is 4.

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3 years ago
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