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Answer:
The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>
Step-by-step explanation:
Given:
A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.
Now, to find the ratio of the area of the school banner to the area of the sign.
Dimensions of school banner :
Length = 54 inches.
Width = 36 inches.
Dimension of school sign:
Length = 17 inches.
So, to we find the width of sign by using cross multiplication method:
Let the width be
So, 54 is equivalent to 36.
Thus, 17 is equivalent to
By cross multiplying we get:
Dividing both sides by 54 we get:
Thus, the width of sign = 11.33 inches.
Now, to get the ratio of the area of the school banner to the area of the sign:
Area of the school banner : Area of the school sign.
=
=
Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.
Answer:
Sample mean =119.42
Median = 92
25% trimmed mean = 102.42
10% trimmed mean = 95.69
Step-by-step explanation:
Data in increasing order :
12 13 20 23 31 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249 262 289 323 388 513
Total no. of observations = 50
Sample mean =
= = 119.42
Median: Since we have even number of observation
Median = =
= 92
10% Trimmed Mean: We remove 5 values from each side
Trimmed set = 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249
Trimmed mean = =
= 102.42
25% Trimmed Mean: We remove 12 values from each side.
Trimmed set = 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141
Trimmed mean = =
= 95.69