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Evgesh-ka [11]
3 years ago
9

Solve for x.

Mathematics
2 answers:
Alex Ar [27]3 years ago
6 0

Answer:


Step-by-step explanation:

3x^2     -   4x    -     2     =   0

<u>Solution:</u>

x     =    2  +  sqrt  10/3

x      =    2    -  sqrt  10/3

<u>Decimal:      </u>

x      =       1.72076.....

x       =        0.38743.....



<u>Solve Quadratic equation:</u>

3x^2   -     4x     -   2   =   0

<u>Use quadratic formula:</u>

a    =    3

b     =      -4

c       =    -2

<u>Showing Work:</u>

x     =      -b +/-  sqrt b^2   -  4ac/2a

x       =       -( -4) +/-  sqrt (-4^2)  -   4(3) ( -2)/ 2(3)

x       =     4 +/-   sqrt 40/6

<u>Ans:   x      =    2/3     +   1/3   sqrt 10    or      x    =    2/3   +     -1/3  sqrt 10</u>


   

Hope that helps!!!!!!                    : )                      -P-        


Sphinxa [80]3 years ago
4 0

<u>Answer</u>

1.72   or    -0.387


<u>Explanation</u>

3x²-4x-2=0

3x²-4x = 2

x² - (4/3)x = 2/3

x² - (4/3)x + (2/3)² = 2/3 + 4/9

(x - 2/3)² = 10/9

x - 2/3 = √10/3                            or     x - 2/3 = -√10/3

x = √10/3 + 2/3                           or     x = -√10/3 + 2/3

   = 1.72                                or                 = -0.387





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What set of reflections would carry trapezoid ABCD onto itself? (1 point) Trapezoid ABCD is shown. A is at negative 5, 1. B is a
amid [387]

Answer:

y=x, x axis,  y=x, y axis

Step-by-step explanation:

If a point A(x, y) is reflected along the y = x line, the new coordinates would be A'(y, x)

If a point A(x, y) is reflected across the x axis, the new coordinates would be A'(x, -y)

If a point A(x, y) is reflected along the y axis, the new coordinates would be A'(-x, y)

Firstly reflect Trapezoid ABCD along the y = x line to give:

A (-5, 1) ⇒ A'(1, -5). B (-4, 3) ⇒ B'(3, -4). C (-2, 3) ⇒C'(3, -2). D (-1, 1) ⇒ D'(1, -1)

Secondly reflect along the x axis to give:

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Thirdly reflect along the y = x line to give:

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Lastly reflect along the y axis to give:

A"'(5, 1) ⇒ A""(-5, 1), B"'(4, 3) ⇒ B""(-4, 3), C"'(2, 3) ⇒ C""(-2, 3), D"'(1, 1) ⇒ D""(-1.1)

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