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AleksAgata [21]
3 years ago
14

Letters in the word mathematics

Mathematics
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

<em>Answer is</em><em> </em><em>given below</em><em> </em><em>.</em>

Step-by-step explanation:

Letters in the word "<em>MATHEMATICS</em><em> </em><em>"</em>

<em>M</em><em>,</em><em>A</em><em>,</em><em>T</em><em>,</em><em>H</em><em>,</em><em>E</em><em>,</em><em>I</em><em>,</em><em>C</em><em>,</em><em>S</em><em>.</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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Answer:

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Step-by-step explanation:

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2 years ago
The area of a playground is 2,400 square yards, and the width is 40 yards. What is the length of the playground? PLEASE HELP
Dmitrij [34]
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5 0
2 years ago
1. Consider the data set 1,2,3,4,5,6,7,8,9.
ivanzaharov [21]

Answer:  a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

Since we have given that

1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5

Median = (\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

5 0
3 years ago
At an animal shelter there are 15 dogs 12 cats 3 snakes and 5 parakeets what percent less parakeets are there than dogs
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3 0
3 years ago
Mary throws her Grandma’s favorite crystal dish out the second floor window, which is 6 meters from the ground. She is really up
wlad13 [49]

we know that

acceleration due to gravity is 9.8m/s^2

so, we get

a(t)=9.8

and acceleration will always be constant

we know that

integral of acceleration is velocity

so, we can integrate both sides

\int \:a\left(t\right)dt=\int \:9.8dt

v(t)=9.8t+C

we are given

v(0)=35m/s

we can use it and find C

v(0)=9.8*0+C

35=9.8*0+C

C=35

now, we can plug it back

v(t)=9.8t+35

we know that

integral of velocity is height

we can integrate it again

\int \:v\left(t\right)dt=\int \:\left(9.8t+35\right)dt

s(t)=\int \:\left(9.8t+35\right)dt

s(t)=4.9t^2+35t+C

now, we have

s(0)=6

we can use it and find C

s(0)=4.9(0)^2+35(0)+C

6=4.9(0)^2+35(0)+C

now, we can plug back C

C=6

and we get

s(t)=4.9t^2+35t+6.............Answer

4 0
3 years ago
Read 2 more answers
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