It is always because if you have an improper fraction, the larger number is always the numerator. To get a reciprocal, you flip the fraction so that the denominator is the numerator, and vice versa. If the numerator is always bigger, and you make it the denominator, it would be proper.
Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
You factor the numerator and denominator and cancel the common factors. So maybe that should help you
Answer:
20.875
Step-by-step explanation:
divide it and this is what get.
