Answer:
a. The probability is not equal to 1
b. P (A') = 0.70
c. P ( A U B ) = 0.80
d. P ( A' ∩ B' ) = 0.20
Step-by-step explanation:
a. Because these A and B are disjoint
b. since the probability of A is 0.30 then the probability of A compliment is
P(A compliment ) = 1 - P (A)
P(A compliment ) = 1-0.30
P(A compliment ) = 0.70
c. Since event are disjoint then intersection of A and B is 0, so probability of A U B is;
P ( A U B ) = P (A) + P(B) - P(A∩ B)
P ( A U B ) = 0.30 + 0.50 - 0
P ( A U B ) = 0.80
d. The inetrsection of compilments of A and B are:
by using De Morgan's Law we have,
P ( A' ∩ B' ) = P [(A U B )']
P ( A' ∩ B' ) = 1 - P ( A U B )
P ( A' ∩ B' ) = 1 - 0.80
P ( A' ∩ B' ) = 0.20
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)
we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>
step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3
the midpoint AB is (3√2,2√3)
the answer isthe abscissa of the midpoint of the line segment is 3√2
see the attached figure
Answer:
<1 = 93 (vertical opposite angle are equal)
Step-by-step explanation:
The point (7,-4) lies in Quadrant 4. Where it’s ( + , - )
hope this helps !