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VikaD [51]
3 years ago
11

9. During the past week, Mr. Hamilton gave one quiz and one exam to his high school algebra class.

Mathematics
1 answer:
Kamila [148]3 years ago
6 0

<em>Missing Information:</em>

<em>It takes Mr. Hamilton 1/15  of an hour to grade one student’s exam and 1/30  of an hour to grade one  student’s quiz.</em>

Answer:

Total\ Time = \frac{x}{10}

Step-by-step explanation:

Given

Exam = \frac{1}{15}hr

Quiz = \frac{1}{30}hr

Required

Determine the time spent on x students

First, we need to determine the total time spent on 1 student

Time = Exam + Quiz

Time = \frac{1}{15} + \frac{1}{30}

Take LCM

Time = \frac{2 + 1}{30}

Time = \frac{3}{30}

Time = \frac{1}{10}

Next is to determine the total time on x students:

Total\ Time = \frac{1}{10} * x

Total\ Time = \frac{x}{10}

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Mary says that -5 x 2 = -3. Explain the mistake Mary made and write the correct number sentence including the correct answer.
stira [4]

Answer:

it should be -10

Step-by-step explanation:

5 x 2 is 10 but you add the negative. Mary added instead of multiplied.

4 0
3 years ago
Read 2 more answers
I need help on this:
marishachu [46]

The given number sentence is simplified as 1 3/5

<u>Step-by-step explanation:</u>

The given number sentence is 2-4/5 x 1/2

  • In order to solve this, the operations must be performed based on the BODMAS rule.
  • This means that, the operations should be performed in the order of Bracket, Of, Division, Multiplication, Addition and Subtraction.

Here, based on that above rule, the multiplication must be done in the first step and then subtraction should be done in the next step.

⇒ 2 - 4/5 × 1/2

⇒ 2 - 4/10

⇒ 2 - 2/5

Therefore, the given expression is reduced to 2- 2/5

cross multiply the denominator 5

⇒ (10-2) / 5

⇒ 8/5

Now, the expression is reduced to single term 8/5.

To further reduce the term, divide 8 by 5.

  • The quotient is 1.
  • The remainder is 3.
  • The divisor is 5.

The answer is written in the form of Quotient(Remainder/ divisor)

⇒ 1 3/5

8 0
3 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

6 0
3 years ago
The parabola with equation $y=ax^2+bx+c$ is graphed below:
Mashutka [201]

Answer:

m-n=2

Step-by-step explanation:

Instead of using the standard form, we can use the vertex form of a quadratic equation:

f(x)=a(x-h)^2+k

Where a is the leading coefficient, and (h, k) is our vertex.

Our vertex point is at (2, -4). So, let’s substitute 2 for h and -4 for k:

f(x)=a(x-2)^2-4

Now, we need to determine a.

We know that it passes through the point (4, 12). So, when x is 4, y must be 12. In other words:

12=a((4)-2)^2-4

Solve for a. Subtract within the parentheses:

12=a(2)^2-4

Add 4 to both sides:

16=a(2)^2

Square:

16=4a

Solve:

a=4

Thererfore, the value of a is 4.

So, our function is:

f(x)=4(x-2)^2-4

Now, let’s find our roots. Set the equation to 0 and solve for x:

0=4(x-2)^2-4

4=4(x-2)^2\\1=(x-2)^2\\x-2=\pm1 \\ x=2\pm1 \\ x=3\text{ or } 1

So, our roots are 1 and 3.

The greater root is 3 and the lesser root is 1.

Therefore, m-n, where m>n, is 3-1 or 2.

Our final answer is 2.

4 0
3 years ago
Read 2 more answers
Rewrite the equation x = 65 - 60p by factoring the side that contains the variable p.
grigory [225]

Answer: x=5(13-12p)


Step-by-step explanation:

Given equation: x=65-60p

\\\Rightarrowx=(5\times13)-(5\times12)p

Since 5 is the greatest common factor of 65 and 60 in the given expression.

Therefore, the above expression can be written as

x=5(13-12p)

Hence, by factoring the side that contains the variable p we have the expression x=5(13-12p).




7 0
3 years ago
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