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9966 [12]
3 years ago
14

Which of the following relations has a domain of {2, 3, 6}? Choose all that apply. {(3, 3), (2, 2), (3, 2), (6, 1)} {(3, 1), (6,

4), (2, 4), (6, 5)} {(0, 2), (3, 3), (5, 6)} {(3, 2), (5, 3), (2, 6), (4, 3)}
Mathematics
1 answer:
Ganezh [65]3 years ago
7 0
All except (0,2), (5,6), (5,3), and (4,3).  The domain is the x and the range is the y, so the x coordinate has to either be 2, 3, or 6.
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B. Solve the following Polynomials:<br>1. u³ + 64​
Art [367]

Answer:

(4 + u)(16 – 4u + u2)

Step-by-step explanation:

64 + u3.

= 43 + u3.

= (4 + u)(42 – 4.u + u2).

= (4 + u)(16 – 4u + u2).

3 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
how many different possible outcomes exist when each spinner shown below is spun one time? one is numbered from 1-3 and one is 1
Anit [1.1K]

Answer:

there is 7 possible solutions

7 0
3 years ago
Read 2 more answers
Each face of a number cube is a square with a side length of 16 millimeters. What is the total area of all of the faces of the n
kupik [55]

Answer:

1536² mm

Step-by-step explanation:

16 x 16 = 256

256 x 6 = 1536 (6 = number of faces)

1536²mm

6 0
2 years ago
1. Write 33% as a fraction.
Olegator [25]

Answer:

33/100

62%

0.77

0.4

9/10

8 0
2 years ago
Read 2 more answers
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