Let f(x)=x+2 and g(x)=
align="absmiddle" class="latex-formula">+1 .
Graph the functions on the same coordinate plane.
What are the solutions to the equation f(x)=g(x) ?
Enter your answers in the boxes.
x = ___ or x = ____
Graph the functions on the same coordinate plane.
What are the solutions to the equation f(x)=g(x) ?
Enter your answers in the boxes.
x = ___ or x = ____
1 answer:
Answer: x = 0 and x = 1
Explanation:
The image of the graph is in the figure attached.
There you can observe two intersection points which are (0,2) and (1,3), therefore the solutions are x = 0 and x = 1.
You can draw the graph by constructing a table with x from - 2 to 4, like this:
x f(x) = x + 2 g(x) = 2^x + 1
-2 -2 + 2 = 0 2^2 + 1 = 4 + 1 = 5
- 1 -1 + 2 = 1 2^1 + 1 = 2 + 1 = 3
0 0 + 2 = 2 2^0 + 1 = 1 + 1 = 2 => this is one solution
1 1+ 2 = 3 2^1 + 1 = 2 + 1 = 3 => this is the other solution
2 2 + 2 = 4 2^2 + 1 = 4 + 1 = 5
Explanation:
The image of the graph is in the figure attached.
There you can observe two intersection points which are (0,2) and (1,3), therefore the solutions are x = 0 and x = 1.
You can draw the graph by constructing a table with x from - 2 to 4, like this:
x f(x) = x + 2 g(x) = 2^x + 1
-2 -2 + 2 = 0 2^2 + 1 = 4 + 1 = 5
- 1 -1 + 2 = 1 2^1 + 1 = 2 + 1 = 3
0 0 + 2 = 2 2^0 + 1 = 1 + 1 = 2 => this is one solution
1 1+ 2 = 3 2^1 + 1 = 2 + 1 = 3 => this is the other solution
2 2 + 2 = 4 2^2 + 1 = 4 + 1 = 5
You might be interested in
Take the equation <span> h (t) = 73 – 16 t^2 and plugin 9 for h(t) and then solve for t like the following:
</span>9 = 73 - 16 t^2
9 - 73 = 73-73 - 16t^2
-64 = -16t^2
-64 / -16 = -16t^2 / -16
4 = t^2
Now square both sides of 4 = t^2
2 = t
t = 2
Answer = 2 seconds
</span>9 = 73 - 16 t^2
9 - 73 = 73-73 - 16t^2
-64 = -16t^2
-64 / -16 = -16t^2 / -16
4 = t^2
Now square both sides of 4 = t^2
2 = t
t = 2
Answer = 2 seconds