Question

Identify the restrictions on the domain of f(x) = quantity x plus 2 over quantity x minus 3.

Answer 1

For this case we must find the domain of the following function:

$f (x) = \frac {x + 2} {x-3}$

By definition, the domain of a function is given by all the values for which the function is defined. The given function is not defined when the denominator is equal to zero, that is:

$x-3 = 0\\x = 3$

Thus, the domain of the function is given by all real numbers except 3.

Answer:

x other than 3

Answer 2

Answer:

x does no equal 3

Step-by-step explanation: