Question

Harrison went out to buy coffee for his classmates. There are 23 students in his class, counting Harrison himself. Some wanted mochas, and some wanted lattes. At the coffee shop nearby, a mocha costs $4.30, while a latte costs $3.50. If Harrison bought one coffee for each student — including one for himself — and spent $87.70, how many of each coffee did he buy?

Answer 1

Answer:

4.30 + 3.50 =7.80 x 7 = 54.60  7 of each

87.70 -54.60 = 33.10

33.10 = 7 x 3.50 = 24.50 = 7 more latte

$8.60 left over = 2 more mocha

=14 latte and 9 mocha

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let's represent the number of mochas bought with the variable $M$, and the number of lattes bought with the variable $L$.

Since there are $23$ students, the total number of mochas and lattes bought must be $23$. This can be represented with the following equation:

$M + L = 23$

We can also set up another equation based on the total amount spent on the coffe:

$4.30M + 3.50L = 87.70$

If we rearrange the first equation, we can solve for $M$:

$M = 23 - L$

If we substitute this into the second equation, we can solve for $L$:

$4.30(23 - L) + 3.50L = 87.70$

$98.9 - 4.3L + 3.5L = 87.7$

$98.9 - 0.8L = 87.7$

$0.8L = 11.2$

$L = 14$

Subtituting this back into the original equation, we can solve for $M$:

$M + L = 23$

$M + 14 = 23$

$M = 9$

Therefore, 9 mochas and 14 lattes were bought.