Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
Answer:
31
Step-by-step explanation:
Lets say Friday papers are x
Saturday papers are 2x
Total cost of Friday papers are .75x
Total cost of Saturday papers are 3x
.75x+3x=116.25
3.75x=116.25
X=31
Let the number be x.
1st number = x
2nd number = x + 2
3rd number = x + 4
x + x + 2 + x + 4 = -9
3x + 6 = -9
3x = -15
x = -5
1st number = x = -5
2nd number = x + 2 = -3
3rd number = x + 4 = -1
Answer: The numbers are -1, -3, and -5
