Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
Answer:
inverse of sin 1.6
or it can be written as sin^1 1.6
Answer:
Option D
Step-by-step explanation:
Use the Pythagorean theorem to solve this question
a2+b2=c2
c2 is always the hypotenuse, which is what we have to solve.
3^2+ 5^2=
9+25=34
Now we have to square 34 and there is our answer
