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ser-zykov [4K]
2 years ago
5

A shoppers discount club charges a monthly fee of $15 and sells gasoline for $2.05 per gallon. The gas station across the street

sells gasoline for $2.35 per gallon and charges no fee. How many gallons of gasoline would you have to buy in one month to spend the same amount at either store?
Mathematics
1 answer:
svet-max [94.6K]2 years ago
3 0
$15.75 dnnddbbd d d d Dbdjdhhdhdvdg
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How to solve this equation 7-2a-5-14=-2+3a
SSSSS [86.1K]

To solve 7-2a-5-14=-2+3a :

1) combine like terms: 7-19 - 2a = -2 + 3a, and then -10 = 5a

2) solve this equation for a: a = -10/5 = -2.

The solution of 7-2a-5-14=-2+3a is a = -2.

6 0
3 years ago
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Daniella is interviewing for a job. She wants her take-home pay to be at least $51,000.
Rzqust [24]
The answer is going to be 3,495
4 0
2 years ago
Nvm I got it now lol
Usimov [2.4K]

Answer:

nice bro good for you :)

Step-by-step explanation:

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2 years ago
How many and what is the solution to 2(x − 1) + 3 = 3x − (x + 4)?
Licemer1 [7]

Answer:

0=−5

Step-by-step explanation:

5 0
2 years ago
A culture of bacteria has an initial population of 650 bacteria and doubles every 9 hours. Using the formula Pt=P0⋅2tdP_t = P_0\
Ghella [55]
So is doubling, first off, meaning, if the current amount say P, then when it doubles is 2P, or double that, or P + P, so the rate of growth is 100%, since it's doubling.

and is doing it every 9 hour cycle, thus

\bf \textit{Periodic/Cyclical Exponential Growth}\\\\
A=P(1 + r)^{\frac{t}{c}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &650\\
r=rate\to 100\%\to \frac{100}{100}\to &1.00\\
t=\textit{elapsed time}\to &10\\
c=period\to &9
\end{cases}
\\\\\\
A=650(1 + 1)^{\frac{10}{9}}\implies A=650(2)^{\frac{10}{9}}\implies A=650\sqrt[9]{2^{10}}
4 0
2 years ago
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