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mamaluj [8]
3 years ago
15

Find the value of side a on the right triange, given that side B=12cm and side C=15cm

Mathematics
1 answer:
docker41 [41]3 years ago
3 0
Use Pythagoras's theorem.
a^{2} + b^{2} = c^{2}

Now, minus 12 from 15:
15 - 12 = 3,
which you need to square.
So the length of a = 9cm.

You can also do:
\sqrt{15^{2} - 12^{2} }
Which gets 9.

Hope this helps.

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Linear equations <br><br> (7,1) and (x,4); m=3/4
Julli [10]

Answer:

x = 11

Step-by-step explanation:

Slope(m) is given by:

m = change in y ÷ change in x

3/4 = (4 - 1) ÷ (x - 7)

\frac{3}{4} = \frac{3}{x - 7}

Cross multiplying gives:

3x - 21 = 12

3x = 33 , x = 33/3 = 11

6 0
4 years ago
2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

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3 years ago
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Somebody please helpI have 12 of these type of questions and I am very confused.
lions [1.4K]

Answer:

(1,1)

Step-by-step explanation:

Really simple, just see where they cross because that shows if you plug in the x or y value into the either equation you will get the same value in return.

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