Standard for is x × 10 ^I
where,
I = indice
10 > x < 0
you cannot write this is standard form with putting in what they stand for. However you can simplify it -
4(8m-7n) +6(3n-4m)
32m - 28n + 18n - 24m
8m - 10n
but hey I am from England do what we call standard form might be different
The answer is 76
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Answer:
Step-by-step explanation:
You need to bring the -5 to the left side.
x^2-6x+5=0
Wat two numbers, when multiplied equal to +5? Also when added make the middle term or -6? -5 and -1.
(x-1)(x-5) The x^2 would factor to be x*x
So the answer is the (x-1)(x-5)
Answer:
7 -1 6 | -8
7 -5 7 | 1
0 1 -4 | -5
Step-by-step explanation:
Note that there are four columns in this system, representing the variables x, y and z and constants. So the given matrix pattern is appropriate: It has three columns for the coefficients of x, y and z and one column for the constants.
We need only identify the coefficients and transfer them into the appropriate boxes of the matrix pattern.
We get:
7 -1 6 -8
7 -5 7 1
0 1 -4 -5
