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Trava [24]
2 years ago
14

Q2: Explain the difference between the solution to an equation and the solution to an inequality. (dba 3

Mathematics
1 answer:
CaHeK987 [17]2 years ago
4 0
The solution(s) of a system of linear equations give points of intersection of specific lines or planes.

The solution(s) of a system of linear inequalities give areas of intersection wherein any specific pair of points or lines are solutions.

PROCESS-WISE there are little differences between solving systems. However, multiplication and division by negatives reverses the signs in inequalities. 
 
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Question 32 of 40<br> The ratio<br> opposite<br> hypotenuse<br> describes which function?
Helen [10]

The ratio \frac{Opposite}{Hypotenuse } describes the Sine function . The correct option is C. Sine

<h3>Trigonometry </h3>

From the question, we are to determine the function that the ratio of <em>opposite </em>to <em>hypotenuse </em>describes

By SOH CAH TOA

We have that

Sine = \frac{Opposite}{Hypotenuse }

Cosine = \frac{Adjacent}{Hypotenuse }

and

Tangent = \frac{Opposite}{Adjacent}

Hence, the ratio \frac{Opposite}{Hypotenuse } describes the Sine function . The correct option is C. Sine

Learn more on Trigonometry here: brainly.com/question/956353

#SPJ1

5 0
2 years ago
A rectangular enclosure is to be created using 82m rope.
atroni [7]
Let
x-----> the length of rectangle
y-----> the width of rectangle

we know that 
perimeter of rectangle=2*[x+y]
perimeter of rectangle=82 m
82=2*[x+y]---> divide by 2 both sides---> 41=x+y--> y=41-x---> equation 1

Area of rectangle=x*y
substitute equation 1 in the area formula
Area=x*[41-x]----> 41x-x²

using a graph tool
see the attached figure

the vertex is the point (20.5,420.25)
that means
 for x=20.5 m ( length of rectangle)
the area is 420.25 m²

y=420.25/20.5----> 20.5 m

the dimensions are
20.5 m x 20.5 m------> is a square

the answer part 1) 
<span>the dimensions of the rectangular with Maximum area is a square with length side 20.5 meters
</span>
Part 2)<span>b) Suppose 41 barriers each 2m long, are used instead. Can the same area be enclosed?
</span>divide the length side of the square by 2
so
20.5/2=10.25--------> 10 barriers
the dimensions are 10 barriers x 10 barriers
10 barriers=10*2---> 20 m

the area enclosed with barriers is =20*20----> 400 m²

400 m² < 420.25 m²
so

the answer Part 2) is 
<span>the area enclosed by the barriers is less than the area enclosed by the rope
</span>
Part 3)<span>How much more area can be enclosed if the rope is used instead of the barriers
</span>
area using the rope=420.25 m²
area using the barriers=400 m²

420.25-400=20.25 m²

the answer part 3) is
20.25 m²

6 0
3 years ago
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