Question

What is the approximate volume of a cone with a height of 9 ft and radius of 3 ft?

Answer 1

Answer:  The answer is 84 ft³.

Step-by-step explanation:  Given that a cone has a height of 9 ft and a radius of 3 feet. We are to find the approximate volume of the cone.

Also, it is given to assume that

$\pi=3.14.$

We know that the volume of a cone with height 'h' and radius 'r' is given by

$V=\dfrac{1}{3}\pi r^2h.$

Here, r = 3 ft and h=9 ft.

Therefore, the volume of the cone will be

$V=\dfrac{1}{3}\pi r^2h=\dfrac{1}{3}\times 3.14\times 3^2\times 9=\dfrac{254.34}{3}=84.78\sim 84~\textup{ft}^3.$

Thus, the required volume will be 84 ft³.

Answer 2

Cone Volume = (π • r² • h) ÷ 3

Cone Volume = (3.14 * 3^2 * 9) / 3

Cone Volume = (3.14 * 27)

Cone Volume = 84.82 cubic feet