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Alex Ar [27]
2 years ago
9

What is the approximate volume of a cone with a height of 9 ft and radius of 3 ft?

Mathematics
2 answers:
Nesterboy [21]2 years ago
7 0

Answer:  The answer is 84 ft³.

Step-by-step explanation:  Given that a cone has a height of 9 ft and a radius of 3 feet. We are to find the approximate volume of the cone.

Also, it is given to assume that

\pi=3.14.

We know that the volume of a cone with height 'h' and radius 'r' is given by

V=\dfrac{1}{3}\pi r^2h.

Here, r = 3 ft and h=9 ft.

Therefore, the volume of the cone will be

V=\dfrac{1}{3}\pi r^2h=\dfrac{1}{3}\times 3.14\times 3^2\times 9=\dfrac{254.34}{3}=84.78\sim 84~\textup{ft}^3.

Thus, the required volume will be 84 ft³.

mr Goodwill [35]2 years ago
4 0
<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3

</span></span></span></span><span>Cone Volume = (3.14 * 3^2 * 9) / 3
</span>
<span>Cone Volume = (3.14 * 27)

</span><span><span>Cone Volume = </span>84.82 cubic feet

</span>
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Complete Question

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2

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Step-by-step explanation:

From the question we are told that

     The population  mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

     The  sample size is  n =  50

     The  sample standard deviation is  6.7 weeks.

      The  sample mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

       

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      The  alternative hypothesis  H_a  :  \mu < 15.9

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=>    z =  \frac{13.4 - 15.9}{\frac{6.7}{\sqrt{50}}}

=>     z =  -2.64  

   

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