The answer would be the Third Option, "Never".
<span>If lim(x->3) f(x)=7, then </span><span>f(3) = 7.</span>
Answer:
Hello!
Step-by-step explanation:
How do we solve for j when there is no equation with j in it to solve for j. <em><u>Hope we can help you with this when we get a equation! </u></em>
Answer:
(x^2 + x -1) x (x^2+3x-3)
Step-by-step explanation:
-6x-5+x^4+4x^3-x^2+8
-6x+3+x^4+4x^3-x^2
-6x+3+x^4+x^3+3x^3-x^2
-3x-3x+3+x^2 x(x^2+x-1)+3x^3 +3x^2-3x^2
3x *(x^2+x+x-2)-3(x^2+x-1)+x^2 *(x^2+x-1)
= (x^2+x-1) x (x^2+3x-3)
* means multiply btw
The corresponding values needed will be -23, -8, 7 and 22
<h3>Functions and Tables</h3>
Given the function y = 5x - 8
<h3>Get the domains and range</h3>
We are to get the range of the function for the given domains
If the value of x is -3
y = 5(-3) - 8
y = -15 - 8
y = -23
If the value of x is 0
y = 5(0) - 8
y = 0 - 8
y = -8
If the value of x is 3
y = 5(3) - 8
y = 15 - 8
y = 7
If the value of x is 6
y = 5(6) - 8
y = 30 - 8
y = 22
Hence the corresponding values needed will be -23, -8, 7 and 22
Learn more on tables of function here: brainly.com/question/3632175
