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Dmitry_Shevchenko [17]
3 years ago
12

What is the quadratic. Formula?

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Answer:

x =   \frac{ - b   ± \sqrt{ {b }^{2}  -  4ac } }{2a}

Step-by-step explanation:

For example, we'll use this quadratic equation.

{x}^{2}  + 5x + 6

To understand how to plug it into the formula we need to know what each term represents.

a {x}^{2}  + bx + c

So the equation above would be put into the formula like this.

x =  \frac{ - 5± \sqrt{ {5}^{2}  -  4(1)(6) } }{2(1)}

Then we would solve

\frac{ - 5± \sqrt{25 - 24} }{2}  \\ \\  =  \frac{ -5±1}{2}

Now, the equation will branch off into one that solves when addition and one when subtraction.

\frac{ - 5 + 1}{2}  =  \frac{ - 4}{2}  =  - 2 \\  \\   \frac{ - 5 - 1}{2}  =  \frac{ - 6}{2}  =  - 3

So x={-3, -2} (-3 and -2)

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Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

6 0
4 years ago
a classroom has 24 bulbs and four of the bulbs are failed. how many arrangements are the four failed bulbs are possible?
astraxan [27]

Answer:

Step-by-step explanation:

3

8 0
1 year ago
Can u help me please
xz_007 [3.2K]
<h3>Answer:  y = 3x+18</h3>

Slope = 3

Y intercept = 18

==================================================

Work Shown:

m = slope

m = (y2-y1)/(x2-x1)

m = (0-(-9))/(-6-(-9))

m = (0+9)/(-6+9)

m = 9/3

m = 3 ... is the slope

-------

y = mx+b

y = 3x+b .... plug in the slope

-9 = 3(-9)+b ... plug in the point (x,y) = (-9,-9)

-9 = -27+b

-9+27 = -27+b+27 .... adding 27 to both sides

18 = b

b = 18 ... is the y intercept

---------

We found that m = 3 is the slope and b = 18 is the y intercept

y = mx+b turns into y = 3x+18

8 0
3 years ago
Write the equation in Standard Form. y = -2x + 5*
Ber [7]

Answer:

  • 2x + y = 5

Step-by-step explanation:

<u>Standard form is:</u>

  • ax + by = c

<u>Given</u>

  • y = -2x + 5

<u>Converting to standard form</u>

  • y = -2x + 5
  • 2x + y = 2x - 2x + 5
  • 2x + y = 5

Correct option is the first one

8 0
3 years ago
Please I could really use some help on this (50 points, 5 stars and Brainliest)
jarptica [38.1K]

Answer:

(a)A(n)=5500(1.01)^{4n}

(b)$5955.71

(c)15.02 years

Step-by-step explanation:

For an initial principal P deposited in an account at an annual interest r compounded for a number of period k, the amount in the account after n years is given by the model:

A(n)=P(1+\dfrac{r}{k})^{nk}

(a)Aunt Ga Ga gave you $5,500 to save for college.

P=$5,500

Annual Interest, r=4%=0.04

Since interest is compounded quarterly, Number of Periods, k=4

Therefore, an exponential function modeling this situation is:

A(n)=5500(1+\dfrac{0.04}{4})^{4n}\\A(n)=5500(1+0.01)^{4n}\\$Simplified\\A(n)=5500(1.01)^{4n}

(b)After 2 years, i.e. when n=2

A(2)=5500(1.01)^{4*2}\\=\$5955.71

(c)When A(n)=$10000, we have:

10000=5500(1.01)^{4n}\\$Divide both sides by 5500\\(1.01)^{4n}=\dfrac{10000}{5500} \\$To solve for n, we change to logarithm form\\Log_{1.01}\dfrac{10000}{5500}=4n\\= \dfrac{ Log \dfrac{10000}{5500}}{Log 1.01}=4n\\4n=60.08\\n=60.08 \div 4\\n=15.02\\$Therefore, in 15.02 years, the account would be worth $10,000.

6 0
3 years ago
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