from question d = 16t^2 = 56-4t
=》 16t^2 -56 + 4t =0
=》 4t^2 - 14 + t = 0
=》 (4t-7)(t+2) =0
=》 t = 1.75 seconds
Answer:
a. 5% of the employees will experience lost-time accidents in both years
b. 24% of the employees will suffer at least one lost-time accident over the two-year period
Step-by-step explanation:
a. What percentage of the employees will experience lost-time accidents in both years?
20% last year, of those who suffered last year, 25% during this year. So

5% of the employees will experience lost-time accidents in both years.
b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?
5% during the two years.
10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.
So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.
First year yes, not on the second.
75% of 20%. So, total:

24% of the employees will suffer at least one lost-time accident over the two-year period
Answer:
3/5 of the students in the class are not in accounting majors
Step-by-step explanation:
The total number of males in the class is 3/8
3/5 of them are accounting majors
The ones who are not in accounting majors are;
3/8 - 3/5 = 9/40
The total number of female students in the class is;
8/8 - 3/8 = 5/8
1/4 of them are accounting majors
The ones who are not in accounting majors are;
5/8 - 1/4 = 3/8
Total number of students not in accounting majors;
9/40 + 3/8
= 24/40
= 3/5
-2.88, -0.37,0.19, 0.91, 1.46