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arsen [322]
3 years ago
5

Can anyone help me please

Mathematics
1 answer:
Nady [450]3 years ago
6 0

Yo sup??

since WY is the perpendicular bisector we can say

3x-5=2x+3

x=8

Hope this helps

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Help with this pls.
Phoenix [80]

Answer:

20 = AC

Step-by-step explanation:

AB+BC = AC

11+9 = AC

20 = AC

6 0
3 years ago
The Gonzales family has three children. On summer break they went to an amusement park they bought 3 child tickets for 18.50 and
sergiy2304 [10]

Answer:

= 24.5

Step-by-step explanation:

1 child ticket = 18.50 and they bought 3 so 18.50 x 3 = 55.5

55.5 + 2 adult tickets = 104.50

104.50 - 55.5 = 2 adult tickets

= 49 for 2 adult tickets

49/2 = 1 adult tickets

= 24.5

4 0
2 years ago
Solve by Substitution. <br> 3x+2y=-4 <br> y=4x-2
qwelly [4]

x=0

y=-2

You'd put them in an ordered point, so (0,-2).

8 0
3 years ago
Read 2 more answers
Guys plzzz help me i don't know how to figure out this question 10(6x+7)=26
Mekhanik [1.2K]
What is x
First you use distributive property
60x+70=26
Next subtract 70 on both sides which gives you -44
60x=-44
Then you divide 60 into -44 which will give you -1.36__36 is repeathing
so X=-1.36 repeading
7 0
3 years ago
Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?
Anit [1.1K]

Answer:

\dfrac{p^{7} q}{160}

Step-by-step explanation:

\dfrac{(4p^-4 q)^-2}{10pq^-3} =

= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}

= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}

= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}

= \dfrac{1}{160}p^{7} q

= \dfrac{p^{7} q}{160}

4 0
3 years ago
Read 2 more answers
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