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victus00 [196]
3 years ago
14

A lock is numbered from 0 to 49. Each combination uses three numbers in a right, left, right pattern. Find the total number of p

ossible combinations for the lock.
Mathematics
1 answer:
expeople1 [14]3 years ago
4 0
We did this few days ago .
50 ( because 49 And 0 ) put to the third power because combination uses 3 numbers.
Sooo....
50.3 (50 to the third power)
50•50•50
125000
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Que is on pic.i can't able to type in text.
ad-work [718]
It's not difficult to compute the values of A and B directly:

A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}
A=\tan^{-1}(\sin\theta)-\dfrac\pi4

B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt
B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}
B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2

Let's assume 0, so that |\csc\theta|=\csc\theta.

Now,

\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}
\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}
\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)
\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in A and B.
3 0
2 years ago
A letter is randomly chosen from the word EXCELLENT. Write each probability as a fraction, decimal, and a percent.
Sergio [31]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete. A complete question is in the form:

A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.

Solution:

The total number of letters found in the word EXCELLENT = 9

i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3

Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3

probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%

ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6

Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3

probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%

7 0
3 years ago
Write an expression to represent:<br> Eight more than the product of two and a number <br> x<br> xx.
gizmo_the_mogwai [7]

Answer:

2x+8

Step-by-step explanation:

7 0
3 years ago
I need help please help me please if you have done this
Ludmilka [50]

Answer:x>-1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
List the perfect cubes between 1,000 and 3,000 that are odd
Bogdan [553]
<span><span>1331 and 2197 is your Answer</span></span>
5 0
3 years ago
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