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qaws [65]
3 years ago
13

I need help please help me please if you have done this

Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0

Answer:x>-1

Step-by-step explanation:

GarryVolchara [31]3 years ago
3 0

Answer:

x>-1

Step-by-step explanation:

On the number line you can see that x is greater than -1

By the way the dark blue line represents what x equals :)

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Eight times the sum of a number and 2 equals 4
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For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

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2 years ago
If point C is between A and B, then AC + CB=_____<br><br> A. ABC<br> B. BC<br> C. AB<br> D. CA
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The answer is C. AB. The total line segment is ACB, or AB, because C is in between A and B. If you are adding AC and CB together, you are adding the two parts of the line together.

I hope this helps :)

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