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zubka84 [21]
3 years ago
14

List the perfect cubes between 1,000 and 3,000 that are odd

Mathematics
1 answer:
Bogdan [553]3 years ago
5 0
<span><span>1331 and 2197 is your Answer</span></span>
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Ashton bought DVD at the price of $20. If he also paid 8.5% sales tax, which is closest to the total amount that Ashton paid for
Anuta_ua [19.1K]

Answer:

A

Step-by-step explanation:

7 0
2 years ago
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Brainliest to the correct answer, but answer ASAP
Lyrx [107]

Answer:

B) 25 / 8

Step-by-step explanation:

We know that pi = 3.14*, or "3 and a little bit more". 25/8=3.125 which is approximately pi.

7 0
2 years ago
Which equation represents the slope-intercept form of the line below?
steposvetlana [31]

Answer:

y=\frac{1}{4} x-5

Step-by-step explanation:

Slope intercept from is represented as :

y = mx + b

So, plugging in the numbers it would look like this :

y=\frac{1}{4} x-5

Hope this helps. Please mark brainliest!

3 0
3 years ago
PLEASE HELP!!!!<br> I need to solve for a, b, and c
nirvana33 [79]

Answer:

  • 25000 seats in section A
  • 14100 seats in sectin B
  • 10900 seats in section C

Step-by-step explanation:

The problem statement tells you half the total number of seats are in section A, so you already know that there are 25000 A seats. The revenue from those seats is

... 25000×$25 = $625,000

so the revenue from B and C seats must total

... $1,070,500 - 625,000 = $445,500

If all 25000 of the B/C seats were C seats, the revenue would be

... 25000×$15 = $375,000

The actual revenue from those seats is $445,500 -375,000 = $70,500 more than that. We know each B seat generates $5 more revenue, so there must be ...

... $70,500/$5 = 14,100 . . . . B seats

Then the balance of the 25000 B and C seats are C seats:

... 25,000 - 14,100 = 10,900 . . . . C seats

_____

<em>Alternate Solution Method</em>

The new Brainly answer format requires the answer be supplied before the working. In order to find the answer quickly so that I can fill in that section, I used a matrix method for solving the problem. The problem equations can be written ...

  • a + b + c = 50000
  • a - b - c = 0
  • 25a + 20b + 15c = 1070500

so the augmented matrix is ...

\left[\begin{array}{cccc}1&1&1&50000\\1&-1&-1&0\\25&20&15&1070500\end{array}\right]

A graphing calculator can be used to find the solution to this, generally using a function that produces the reduced row-echelon form. The attachment shows the solution using a TI-84 calculator.

___

<em>Comment on the Working</em>

Since the number of A seats is equal to the total of B and C seats, the number of A seats must be half the total number of stadium seats. Having figured that out, the problem is reduced to one of finding the mix of B and C seats that will produce the remaining revenue.

As with many mixture problems, it is convenient to look at differences. Start with the assumption that all of the desired revenue comes from the least contributor. Here, that is C seats. Then figure the difference that using a B seat makes ($20 -15 = $5) and the difference of the actual revenue and the amount that you got by assuming all C seats: 445,500 -375,000 = 70,500. Since replacing a C seat by a B seat adds $5 to the revenue, it is easy to figure the number of such replacements required in order to raise the revenue by $70,500.

If you write the equation for B seats, you find the solution to the equation mirrors this verbal description:

... 20b + 15(25000-b) = 445,500

... 5b = 445,500 - 375000 . . . . simplify, subtract 375000

... b = 70500/5 = 14100

8 0
3 years ago
The ages of the people who came to a birthday party are shown below. Which statements must be true according to the histogram? C
spayn [35]
From the histogram it can be seen that
1.) the data is not qualitative. (<span>Qualitative data is typically descriptive <span>data and is not measured by a number but age is measured by a number).
2.) </span></span><span>The data is not skewed right. (</span><span>For a right skewed distribution, the tail of the distribution on the right hand (positive) side is longer than on the left hand side).
3.) </span><span>There were 31 people at the party. (The total number of people at the party from the histogram is given by the sum of the heights of the bars of the histogram = 5 + 13 + 8 + 3 + 2 = 31).
4.) </span><span>There were children at the party. (From the histogram, there were 5 poeple aged 20 and below, which we can describe as children).
5.) </span><span>The most common age of the attendees was not 13 years old. (The mode (i.e. most occuring frequency) of a distribution is represented by the height of the tallest bar of the histogram. From the histogram, the tallest bar represents the ages between 21 to 40)
6.) </span><span>The majority of the people at the party were less than 61 years old. (From the histogram, there were 5 + 13 + 8 = 26 people below the age of 61 in the party and 3 + 2 = 5 people above the age of 60 in the party).

Therefore, the </span><span>statements that must be true according to the histogram are
</span><span>There were 31 people at the party.
</span><span>There were children at the party.
and
</span><span>The majority of the people at the party were less than 61 years old.</span>
5 0
2 years ago
Read 2 more answers
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