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umka21 [38]
3 years ago
9

Solve the equation. (r-3)(r+6)=0

Mathematics
2 answers:
klemol [59]3 years ago
7 0

Answer:

r^2 = -3

Step-by-step explanation:

lesya692 [45]3 years ago
5 0

Answer:

r = 3 or r = -6

Step-by-step explanation:

Solve for r over the real numbers:

(r - 3) (r + 6) = 0

Split into two equations:

r - 3 = 0 or r + 6 = 0

Add 3 to both sides:

r = 3 or r + 6 = 0

Subtract 6 from both sides:

Answer:  r = 3 or r = -6

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Solve for x <br> - 3 (x - 4) = 2x + 4x + 5
In-s [12.5K]

Answer:

x=\frac{7}{9}

Step-by-step explanation:

-3(x-4)=2x+4x+5

distribute -3 into (x-4)

-3x+12=2x+4x+5

combine like terms

-3x+12=6x+5

subtract 6x on both sides

-3x-6x+12=5

combine like terms again

-9x+12=5

subtract 12 on both sides

-9x=-7

divide both sides with -9

\frac{-9x}{-9} \frac{-7}{-9}

x=\frac{7}{9\\}

hope this helps

3 0
3 years ago
8,11, and 14 please.<br> Thank you
stellarik [79]
8= 266.9
11= 91.06
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4 years ago
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X^2 + 2x + 5 find the zeros
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Answer:

Step-by-step explanation:

This is what I got

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3 years ago
Which complex number will be plotted below the real axis and to the right of the imaginary axis?
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Since below and to the right is in the FOURTH QUADRANT
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Do the following lengths form a right triangle?​
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