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zmey [24]
3 years ago
5

PLEASE HELP THIS IS DUE TODAY!!!

Mathematics
2 answers:
Hunter-Best [27]3 years ago
7 0

Answer:

6/28 + 3/4 = 3/14 + 3/4 = 2/28

Step-by-step explanation:

astraxan [27]3 years ago
7 0

Answer:

27/28

Step-by-step explanation:

To get this answer, you need a common denominator. In this case, a common denominator would be 28. So, you leave 6/28 the same. Now, you need 2 convert 3/4 to 28ths. So, 4 (denominator) times what is 28? Well, 4 times 7 is 28. Whatever you do to the top, you do the bottom. So 3 times 7 is 21. Now, you have an equivalent fraction that is 21/28. Now you can add.

So, 6/28 + 21/28 is equal to 27/28.

Hope this helps you! :)

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What are all the integers
makvit [3.9K]
All of the positive and negative numbers are integers.
7 0
4 years ago
In a study of pleas and prison​ sentences, it is found that 6060​% of the subjects studied were sent to prison. Among those sent
Dovator [93]

Answer:

a. 40 %

b. 34.3 % ( approx )

Step-by-step explanation:

Let S is the event of the subjects studied that were sent to prison,

S' is the event of the subjects studied that won't sent to prison,

G is the event of pleading guilty,

G' is the event of not pleading guilty,

According to the question,

P(S) = 60% = 0.6 ⇒ P(S') = 1 - P(S) = 1 - 0.6 = 0.4,

P(S∩G) = 46% of 60% = 0.46 × 0.60 = 0.276,

P(S'∩G) = 36% of 40% = 0.36 × 0.40 = 0.144,

P(G) = P(S∩G) + P(S'∩G) = 0.276 + 0.144 = 0.42

a. The of getting someone who was not sent to prison, P(S') = 0.4,

b. the probability that this person was not sent to prison when it is given that the subject entered a guilty​ plea,

P(\frac{S'}{G})=\frac{P(S'\cap G)}{P(G)}=\frac{0.144}{0.42}\approx 0.343=34.3\%

7 0
4 years ago
if cot theta = -24/7 and cos theta < 0, name the quad in which theta lies, then find the exact value of csc theta
NemiM [27]
Cot θ = -24/7 and cos θ < 0

"cos θ < 0" means cosine is negative

Remember osmething like "ALL students Take Calculus"?

all is positive in quadrant 1
sine/cosecant is positive only in quadrant 2
tangent/cotangent is positive only in quadrant 3
cosine/secant is positive only in quadrant 4

since cot(angent) is the reciprocal of tangent, tangent must also be negative.

tangent is negative in quadrants II and IV
cosine is negative in quadrants II and III

therefore, θ must lie in quadrant II.

remember the tan θ = y / x. it is the y-coordinate divided by the x-coodinate. the y-coordinate would be the height of this 90 degree triangle that forms. the x-coordinate would be the bottom leg of the 90 degree triangle

then cot θ = x / y. therefore, cot θ = -24 / 7 means x = -24 and y = 7. we draw a triangle with these dimensions.

csc θ = r / y = hypotenuse over opposite (when you view the reference angle labeled as the one to base the hypotenuse/oppoiste on) because it is the reciprocal of sine

the hypotenuse can be found w/ pythagorean theorem

hypotenuse = √[(-24)² + 7²] = 25

therefore,
cot θ = 25/7

4 0
3 years ago
8.4×3.7 please show your work on a piece of paper
vekshin1
31.08...........................
5 0
3 years ago
Read 2 more answers
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 <span>16.5 
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