How Do I To Study Effectively?

2 answers:

7 0

Make a reminder on your calender preferably a paper calender that you can hang up in places you can see. Try to study for 30 minutes and no more as studing for more then 30 minutes is actually useless since you forget too much information. Be relaxed but not so relaxed where you lay down on your bed. Sit down at a table where it is quiet to be exact.

dangina [55]2 years ago

4 0

Studying effectively is more harder than it sounds, but the best way to get in the zone in finding what things you prefer. Do you like silence or do you like to listen to music? Another thing when looking forward to studying is determining what you want to accomplish in each study session. To ensure you are studying your brain to the max is making flash cards and testing your own limit’s.

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What is the quotient of 52.7 ÷ 4.25? 20 pts!!

Andrei [34K]

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3 0

3 years ago

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The length of the major axis of the ellipse below is 17 and the length of the red line segment is 6. How long is the blue line s

KatRina [158]

Answer:

<u>Option B. 11</u>

Step-by-step explanation:

See the attached figure

As the figure about an ellipse

So, The sum of distance between A and the foci will be equal the major axis

AB = 6 and the major axis = 17

∴ AB + AC = major axis

∴ 6 + AC = 17

∴ AC = 17 - 6 = 11

<u>So, the length of the blue line segment = 11</u>

5 0

3 years ago

Find all the critical points of the function <img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%20%28x%2B1%29%2F%28x-3%29%20" id="

yulyashka [42]

The function

... y = 1/x

has derivative

... y' = -1/x²

which has no zeros. It is undefined at x=0, the only critical point. The derivative is negative for all values of x, so the function is decreasing everywhere in its domain.

Your function

... y = (x+1)/(x-3)

can be written as

... y = 1 +4/(x-3)

which is a version of y = 1/x that has been vertically scaled by a factor of 4, then shifted 1 unit up and 3 units to the right. Shifting the function to the right means x=3 is excluded from the domain (and the interval on which the function is decreasing).

The critical point is x=3.

The function is decreasing on (-∞, 3) ∪ (3, ∞), increasing nowhere.