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3 years ago

Is the sample mean difference within the confidence interval you computed in part A of this task?

Mathematics

2 answers:

Alenkasestr [34]3 years ago

6 0

Answer:

xit the problem

Step-by-step explanation:

Alex Ar [27]3 years ago

5 0

Not sure so sorry ...........

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If (-3, y) lies on the graph of y = 3-x, then y =

AnnyKZ [126]

Answer:

y=6

Step-by-step explanation:

y=3-x

x=-3

y=3-(-3)

y= 3+3

y=6

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3 years ago

Converting fractions to decimals worksheet 7th grade

oksano4ka [1.4K]

No one can help you if you dont show us the work my dude. But the was to convert them is say you have 1/4 that is 25% of a whole. Sorry i couldnt help more repost the question with a link and people can help then.

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3 years ago

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

3 years ago

Please help need for a test, same thing as last question

Sunny_sXe [5.5K]

141) d
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3 0

3 years ago

Read 2 more answers

Math:What is the value of k? Will Upvote.

mihalych1998 [28]

Are you sure you wrote the question correctly? If I'm doing this right, none of the answers provided are correct.

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3 years ago