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3 years ago

13

Is the sample mean difference within the confidence interval you computed in part A of this task?

2 answers:

Alenkasestr [34]3 years ago

6 0

Answer:

xit the problem

Step-by-step explanation:

Alex Ar [27]3 years ago

5 0

Not sure so sorry ...........

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Help! William earns $13,644.80 per hear, and has his federal taxes withheld from each weekly check. In addition, a total of $53.

leva [86]

So 52 weeks in a year so

13,644.8/52=262.4 per week

53.8 is deducted from 262.4

so the deduction is 53.8 then the answer is
262.4-53.8=208.6

the 10% and 15% part is of the yearly income and 53.8 is 15% of 262.4 so that part doesn't matter

the answer of net pay is 208.6 dollars

8 0

3 years ago

Consider the initial value problem:

Inessa [10]

Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

3 0

3 years ago

Zoe has 5 cucumbers she grew in her garden. she wants to share them equally amoug 4 of her neighbors. how many cucumbers will ea

Kazeer [188]

Each neighbor would get 1 whole cucumber and a 1/4 of a cucumber so it would be 1 and a 1/4

6 0

2 years ago

Read 2 more answers

Does anybody know how to do #11, I figured out #10

const2013 [10]

Answer:

no

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

1. Given the points (-2,4) and (4, -2), find the midpoint between these points.

Naddika [18.5K]

Answer:

(1,1)

Step-by-step explanation:

M=(x1+x2 / 2 , y1+y2 / 2)

M=(-2+4 / 2 , 4+ -2 / 2)

M=(2 / 2 , 2 / 2)

M=(1,1)

5 0

3 years ago