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Kaylis [27]
3 years ago
13

Is the sample mean difference within the confidence interval you computed in part A of this task?

Mathematics
2 answers:
Alenkasestr [34]3 years ago
6 0

Answer:

xit the problem

Step-by-step explanation:

Alex Ar [27]3 years ago
5 0
Not sure so sorry ...........
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The dishes have been cleaned by us into active voice​
KIM [24]

Answer:

the dishes sparkled after we washed them.

Step-by-step explanation:

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A washing machine can hold
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If the washing machine can hold 6 kilograms and he has 4 kilograms of clothes than he would only need to do 1 load
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2 years ago
Which system of the inequalities is shown in the graph
jolli1 [7]

Answer:

C

Step-by-step explanation:

the equation of the parabola is : y = x² - 3x

the equation of the line is y = x + 1

and the shaded area is between those graphs

therefore y ≥ x² - 3x and y ≤ x + 1

6 0
3 years ago
Man Street Florist charges
Digiron [165]

Answer:

2 dozens, $41

Step-by-step explanation:

Given data

Man Street Florist charges

$18 for a dozen roses and a

$5 delivery fee

let the number of dozens be x

and the total charge for x dozens be y

hence

y= 18x+5--------------1

Blooms and Bouquets

charges $20 for a

dozen roses and a $1

delivery fee.

let the number of dozens be x

and the total charge for x dozens be y

hence

y= 20x+1 -------------2

Equate 1 and 2 we have

18x+5=20x+1

20x-18x= 5-1

2x= 4

x= 4/2

x= 2

Hence the number of dozens is 2

the cost is (put x= 2 in eqn 1 or 2)

y= 20(2)+1

y= 40+1

y= $41

6 0
2 years ago
How many 4-digit odd numbers can you make using the digits 1 to 7 if the numbers must be less than 6000? No digits are repeated.
bixtya [17]

Answer:

Step-by-step explanation:he first digit must be a 6, 7, or 8, because the number has to be bigger than 6,000.

The last digit must be a 1, 3, 5, or 7, because the number has to be odd.

So if the first digit is 6 or 8, there are 4 odd-number options for the last digit. If the first digit is a 7, then there are only 3 options for the last digit, as 7 can’t be used twice.

The other two digits can be anything that’s not already used. So for each first-and-last combination of digits mentioned above, there will be six options available for one of the middle digits, and then for each of those 3-digit combinations, five options will be available for the final remaining digit.

At this point, we have everything we need to express this as an equation:

x = (2 x 4 + 1 x 3) x 6 x 5

And then we can simplify and solve:

x = (8 + 3) x 30

x = 11 x 30

x = 330

6 0
2 years ago
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