Answer:
![\large\boxed{A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right] }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-12%5C%5C6%26-8%5Cend%7Barray%7D%5Cright%5D%20%7D)
Step-by-step explanation:
![A=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] \cdot\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] =\left[\begin{array}{ccc}(-3)(-3)+(4)(-2)&(-3)(4)+(4)(0)\\(-2)(-3)+(0)(-2)&(-2)(4)+(0)(0)\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-3%29%28-3%29%2B%284%29%28-2%29%26%28-3%29%284%29%2B%284%29%280%29%5C%5C%28-2%29%28-3%29%2B%280%29%28-2%29%26%28-2%29%284%29%2B%280%29%280%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-12%5C%5C6%26-8%5Cend%7Barray%7D%5Cright%5D)
The answer is 3,600
6(245) + 15(142)
Answer:
8100/8100
I think this the answer to your question.
Step-by-step explanation:
Answer:
z = 2
Step-by-step explanation:
The | | represents absolute value which means the number's distance from 0. Any number's absolute value is going to be a positive number.
So, 5 + what number plus 3 gives you 10?
10 - 3 = 7 and 7 - 5 = 2.
So, |5 + 2| + 3 = 10.
The distance from 5 and 0 is 5
Distance from 2 and 0 is 2
It would take approximately 4.5 seconds
