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myrzilka [38]
3 years ago
11

Brockman Corporation's earnings per share were $3.50 last year, and its growth rate during the prior 5 years was 7.0% per year.

If that growth rate were maintained, how many years would it take for Brockman's EPS to triple?
Mathematics
1 answer:
fredd [130]3 years ago
4 0

Answer:

The number of years it would take is  n  =  2 \ years

Step-by-step explanation:

From the question we are told that

         The earning per share  is  P = $3.50

          The growth rate is  r  =  7.0%

           The duration is t =  5 \ years

Generally the future value is mathematically represented as

          A =  P(1 + \frac{r}{100} )^n

 Where P is the present value

              n is the time period

         A is the future value which is mathematically evaluated as

               A =  3 * P

substituting value

            A =  3 * 3.50

            A = $ 10.5 0

So

      A =  P(1 + \frac{r}{100} )^n

       10.5 =  3.5(1 + \frac{7}{100} )^n

       10.5 = 3.225^n

Taking log of both sides

       log 10.5 = nlog 3.225

        1.0212 = n(0.5085)

         n  =   \frac{1.0212}{(0.5085)}

         n  =  2 \ years

     

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We expect the height of a helium balloon to be increasing, up to the point where it bursts.

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Sergeeva-Olga [200]

Answers:

  • Midline:  y = 0
  • Amplitude = 1.5
  • Function:  g(x) = 1.5sin(0.5x + pi/4)

There are infinitely many possible ways to answer the third part.

===========================================================

Explanation:

The midline is the horizontal line that goes through the center of the sine curve. Visually we can see that is y = 0. Another way we can see this is to note how y = 0 is the midpoint of y = 1.5 and y = -1.5, which are the max and min respectively.

---------

The amplitude is the vertical distance from y = 0 to y = 1.5, and it's also the vertical distance from y = 0 to y = -1.5; in short, it's the vertical distance from center to either the peak or valley.

---------

The general format of a sine curve is

y = A*sin(B(x-C)) + D

where,

  • |A| = amplitude
  • B = variable tied with the period T, specifically B = 2pi/T
  • C = handles the left and right phase shift
  • D = handles the vertical shifting, and y = D is the midline.

In this case, we found so far that

  • |A| = 1.5 which could lead to A = 1.5
  • B = 2pi/(4pi) = 0.5 since T = 4pi is the period
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The only thing we're missing is the value of C, which is the phase shift.

Note the point (pi/2, 1.5) is one of the max points on this curve. Also, recall that sin(x) maxes out at 1 when x = pi/2

This must mean that the stuff inside the sine, the B(x-C) portion, must be equal to pi/2 in order to lead sin(B(x-C)) = 1.

So,

B(x-C) = pi/2

0.5(pi/2-C) = pi/2

pi/4 - C/2 = pi/2

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C = -pi/2

This allows us to update the function to get g(x) = 1.5*sin(0.5(x+pi/2)) which is the same as g(x) = 1.5sin(0.5x + pi/4)

This is one possible answer because we could have infinitely many possible values for C, due to sin(x) = 1 having infinitely many solutions.

Also, you could use cosine instead of sine. Cosine is just a phase shifted version and of sine, and vice versa.

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