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3 years ago

In a football game, a quarterback threw the football 5 yards on one play. What is this distance in inches?

Mathematics

2 answers:

Rudik [331]3 years ago

8 0

Answer:

180 inches.

Step-by-step explanation:

1 yard = 36 inches.

5 yards = 180

multiply everything by 5

yaroslaw [1]3 years ago

6 0

180 inches. 36 inches = 1 yard. hope this helps :)

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The measures of the angles of △ABC are given by the expressions in the table.

antoniya [11.8K]

Answer:

First You add all given angles up to equal 180 to give you x then you plug x into equations

Step-by-step explanation:

A= 125 degrees

C= 35 degrees

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3 years ago

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Read the picture, fhankyou

valentina_108 [34]

Hi,
The second option is the correct answer.

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4 years ago

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Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years Rs.1290 as interest Compound

Natalija [7]

Given info:

Compound Interest = Rs.1290

Rate of Interest = 15% p.a

Time = 2 years

<h3>Formula we have to know:-</h3>

$\dag{\underline{\boxed{\sf{C.I = P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1}}}}$

<u>Where</u>

C.I = Compound Interest

P = Principle

R = Rate of Interest

N = Time

$\textsf{ \underline{Solution-}}\\$

Here

C.I = Rs.1290

R = 15%

N = 2 years

Principle = ?

Now,Calculating the sum (Principle) borrowed by Rachna

$\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}$

Substituting the given values

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}$

$\quad{: \implies{\sf{1290 = P \times {0.3225}}}}$

$\quad{: \implies{\sf{\dfrac{1290}{0.3225} = P}}}$

$\quad{: \implies{\sf{\dfrac{1290 \times 1000}{0.3225 \times 1000} = P}}}$

$\quad{: \implies{\sf{\dfrac{12900000}{3225} = P}}}$

$\quad{: \implies{\sf{\cancel{\dfrac{12900000}{3225}} = P}}}$

$\quad{: \implies{\sf{Rs.4000 = P}}}$

$\quad{\dag{\underline{\boxed{\tt{\blue{Principle} = \purple{Rs.4000 }}}}}}$

$\begin{gathered}\end{gathered}$

<u>Hence,</u>

The sum (Principle) is Rs.4000.

3 0

3 years ago

Please solve this for me

Marrrta [24]

$6 sin² x + 4 cos²x = Stanx$

$Correct option is B)Given, 4cos2x+6sin2x=5$

$⇒4cos2x+4sin2x+2sin2x=5⇒2sin2x=1⇒sin2x=21=(21)2⇒x=nπ±4π$

<h3>Solve any question of Trigonometric Functions with:-</h3>

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2 years ago

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Two pound bags of candy are being used to fill containers that hold 1 1/2 pounds each. How many containers can be filled by each

melamori03 [73]

Answer:

4 Containers Can Be Filled By Each Two Pound Bag Of Candy .

Step-by-step explanation:

GIven Two Pound Bag Of Candy Used To Fill Container That hold $1\frac{1}{2}$ Pound Each .

Now There are 4 Container of Capacity $1\frac{1}{2}$ Pound Needed To fill Exactly 3 two Pound Bags .

Thus 4 container have Total capacity Of 6 Pound . Which Is Easily Filled By The 3 two Pound Bags . ( Without Any Loss )

3 0

3 years ago