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tankabanditka [31]

3 years ago

13

A store manager set up a cardboard display to advertise a new brand of perfume. The display is a square pyramid whose base is 18

inches on each side. The height of each triangular face of the pyramid is 12 inches. How much cardboard was used to make this display?

1 answer:

AleksandrR [38]3 years ago

8 0

I think the answer is 13,824

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On a coordinate plane, how are the locations of the points (1 , -7) and (1 , 7) related?

yan [13]

Answer:

D. Reflection across x-axis

Step-by-step explanation:

When plotting the two points & then connecting the dots, it will not touch y-axis at all - it will be straight line and cross x axis

3 0

3 years ago

Which expression represents the inverse of the function f(x)=4x

Anton [14]

Answer:

$f^{-1}$ (x) = $\frac{x}{4\\}$

Step-by-step explanation:

Let y = f(x) and rearrange making x the subject

y = 4x ( divide both sides by 4 )

x = $\frac{y}{4}$

Change y back into terms of x

$f^{-1}$ (x) = $\frac{x}{4\\}$

4 0

3 years ago

Whats $4.23 divided by 50%

Bezzdna [24]

Here you go 4.32/ 0.50=8.64

3 0

3 years ago

Read 2 more answers

strojnjashka [21]

Answer:

2500 pence (C = 2500)

Step-by-step explanation:

$C = 10t + 20m$

From the given information, t is the number of texts so essentially you will plug in the number of texts provided (150) in the place of the variable t.

$C = 10(150) + 20m$

Apply the same thing to minutes, plug in the number of minutes (50) in the place of the variable m.

$C = 10(150) + 20(50)$

Now multiply the substitutes with the co-efficient.

$C = 1500 + 1000$ (10*150=1500 & 20*50=1000)

Add the addends

C = 2500

7 0

3 years ago

What is the value of \dfrac{d}{dx}\left(\dfrac{2x+3}{3x^2-4}\right) dx d ( 3x 2 −4 2x+3 )start fraction, d, divided by, d, x

stellarik [79]

Answer:

4.

Step-by-step explanation:

We are asked to find the value of expression $\frac{d}{dx}(\frac{2x+3}{3x^2-4})$ at $x=-1$ .

First of all, we will find the derivative of the given expression using "Quotient Rule of Derivatives" as shown below:

$(\frac{f(x)}{g(x)})'=\frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{(g(x))^2}$

$\frac{d}{dx}(\frac{2x+3}{3x^2-4})$

$\frac{\frac{d}{dx}(2x+3)*(3x^2-4)-(2x+3)*\frac{d}{dx}(3x^2-4)}{(3x^2-4)^2}$

$\frac{2*(3x^2-4)-(2x+3)*(6x)}{(3x^2-4)^2}$

$\frac{6x^2-8-12x^2-18x}{(3x^2-4)^2}$

$\frac{-6x^2-18x-8}{(3x^2-4)^2}$

Therefore, our required derivative is $\frac{-6x^2-18x-8}{(3x^2-4)^2}$ .

Now, we will substitute $x=-1$ in our derivative to find the required value as:

$\frac{-6(-1)^2-18(-1)-8}{(3(-1)^2-4)^2}$

$\frac{-6(1)+18-8}{(3(1)-4)^2}$

$\frac{-6+18-8}{(3-4)^2}$

$\frac{4}{(-1)^2}$

$\frac{4}{1}$

$4$

Therefore, the value of expression $\frac{d}{dx}(\frac{2x+3}{3x^2-4})$ at $x=-1$ is 4.

6 0

3 years ago