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Usimov [2.4K]
3 years ago
6

The range of the function y = 2cos x is -2 ≤ y ≤ 2.

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

<u>Answer:</u>

The range of the function y = 2cos x is -2 <y < 2 .

<u>Step-by-step explanation:</u>

We know that cos (0) = 1 and cos (π) = - 1 are the two extreme values which cos x assume when x ∈ R and it is also that cos (x) is a continuous periodic function with period 2π when x ∈ R ,

since ,

cos (x + 2π) = cos x

So, the range of the  function y = 2cos x is -2 <y < 2 .

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The amount of stockholders’ equity as of August 31 of the current year is $26400.

<h3>How to calculate the equity?</h3>

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The domain of startfraction f over g endfraction f g consists of numbers x for which g left parenthesis x right parenthesisg(x)
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The domain of f/g consists of numbers x for which g(x) cannot equal 0 that are in the domains of both f and g.

 

Let’s take this equation as an example:

If f(x) = 3x - 5 and g(x) = square root of x-5, what is the domain of (f/g)x. 


For x to be in the domain of (f/g)(x), it must be in the domain of f and in the domain of g since (f/g)(x) = f(x)/g(x). We also need to ensure that g(x) is not zero since f(x) is divided by g(x). Therefore, there are 3 conditions.

 

x must be in the domain of f: f(x) = 3x -5 are in the domain of x and all real numbers x.

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g(x) can not be 0: g(x) = √(x - 5) and √(x - 5) = 0 gives x = 5 so x ≠ 5.

 

Hence to x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x satisfying x > 5.

 

Thus, satisfying <span>satisfy all three conditions, x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x satisfying x > 5.</span>

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Step-by-step explanation:

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