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3 years ago

6th grade math , help me please :)

Mathematics

2 answers:

Charra [1.4K]3 years ago

7 0

Answer:

(a) 3:5

(b) 15

Step-by-step explanation:

Well first we need to create a ratio for the 5 shades squares and 3 non+shaded squares.

It is asking for unshaded first so our ratio will be,

3:5

(a) 3:5

So if there is 9 unshaded how many shaded is there.

Well we can just make the following ratio 9:x

So 9/3 = 3

Meaning 3*5 = 15

So x = 15

(b) 15

ArbitrLikvidat [17]3 years ago

7 0

Answer:

a) 3/5

b) 15

Step-by-step explanation:

(a)

unshaded: 3

shaded: 5

unshaded to shaded: 3/5

(b)

There are now 3 unshaded squares. You need 9 unshaded squares, so you need to have three times as many total squares as you have now.

Add two more lines just like the given line.

Each new line will have 5 shaded and 3 unshaded squares.

Now you have a total of 9 unshaded and 15 shaded squares.

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Start fraction two minus five x over negative three end fraction plus four less than negative x

Charra [1.4K]

2 - 5x
------- + (-x - 4)
-3

8 0

3 years ago

The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu

Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t - 5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0

3 years ago

Please help must show work there are 5 that I'm stuck on

Cloud [144]

you cannot show too much "work"

basically, you remove what is common to all of the factors, and then put brackets, as it will be multiplied back in, remember that when you multiply exponents with the same base, its same as adding them, so subtract to remove...

you can seperate two of the variables , then factor, then subtract the last one from those two, because it cannot be factored out , as in part2 #2