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olga_2 [115]
3 years ago
11

Andrea is selling candles as a fundraiser. She spent $50 on supplies for making the candles. She plans to sell the candles for $

10 each. The functions of her revenues can be modeled by C(x) = 10x - 50 What is a reasonable range for the function?
Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

A reasonable range for the function is [0, +\infty).

Step-by-step explanation:

Revenues are positive quantities since Andrea is looking for money after expenses, so that reasonable range of the revenue function is [0, +\infty).

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4 0
3 years ago
-(3/4)+1 7/8 divided by 1/2 =n
VashaNatasha [74]

first off, let's convert the mixed fraction to improper fraction and then proceed, let's notice that by PEMDAS or order of operations, the multiplication is done first, and then any sums.

\stackrel{mixed}{1\frac{7}{8}}\implies \cfrac{1\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{15}{8}} \\\\[-0.35em] ~\dotfill\\\\ -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \div \cfrac{1}{2}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \cdot \cfrac{2}{1}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{4} \\\\\\ \cfrac{-3+15}{4}\implies \cfrac{12}{4}\implies 3

5 0
2 years ago
ALGEBRA 1
Gekata [30.6K]
The answer is B. 8x+6. You multiple 3 and x+4 then combine like terms
7 0
3 years ago
Solve the following system of equations 3x+4y=16 and -4x-3y = -19
BigorU [14]
3x + 4y = 16
-4x - 3y = -19

4( 3x + 4y = 16)
3( -4x - 3y = -19)
Distribute
12x + 16y = 64
-12x - 9y = -57
Now subtract both equations
7y = 7
/7 on both sides
y = 1

Substitute y = 1 in one of the equations.
3x + 4y = 16
3x + 4(1) = 16
-4 on both sides
3x = 12
/3 on both sides
x = 4

Answer:
x = 4
y = 1
4 0
3 years ago
Malik’s solution to the equation 2/5x-4y=10 , when x=60, is shown below.
zhenek [66]

Answer:

D. Malik substituted 60 for y instead of x.

Step-by-step explanation:

Look closely at the step by step process.

4 0
3 years ago
Read 2 more answers
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