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sleet_krkn [62]
3 years ago
13

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 8

Mathematics
1 answer:
Zina [86]3 years ago
5 0

Answer:

The weight of large box x = 18.5 kg and weight of small box y= 15 kg

Step-by-step explanation:

Let x represents large boxes and y represents small boxes

our equations will be:

8x + 3y = 193    (i)

2x + 5y = 112     (ii)

By solving above equations we can find value of x and y

Multiply eq (ii) with 4

8x + 20 y = 448

Now subtracting eq (ii) from eq (i),

8x + 3y = 193

8x + 20 y = 448

-------------------------

     -17 y = -255

          y = -255 / -17

          y = 15

Now substituting value of y in eq (i)

8x + 3y = 193

8x + 3(15) = 193

8x + 45 = 193

8x  = 193 - 45

x = 148 / 8

x = 18.5

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For this case we have the following apple picking options, in dozens:

<em>Tyler:</em>

\frac {3} {3} = 1

Tyler picked up a dozen.

<em>Olivia:</em>

\frac {5} {6} = 0.833

Olivia collected 0.833 dozen apples.

<em>Samantha:</em>

\frac {2} {3} = 0.667

Samantha collected 0.667 dozens of apples.

Thus, it is observed that Samantha collected the least amount of apples.

ANswer:

Samantha

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3 years ago
What is the first term of the quotation of the following division problem?
sveticcg [70]

Answer:

I believe it's D.

Step-by-step explanation:

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Hope This Helps!       Have A Nice Day!!

5 0
4 years ago
Can someone help me please <br> I will give brainiest <br> don’t need to show work
4vir4ik [10]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
I don't quite understand
Kamila [148]
This is essentially the game mastermind if you want to look up more about it

the first 2 guesses have a number with the correct value and in the right position "bulls", all three guesses start with a 1, so if 1 were correct in the first position the 3rd guess would have a "bull" too

this means either the 6 or 2 from the first guess and the 7 or 5 from the second are correct in the 2nd or 3rd position

in the 3rd guess the 3rd number is a 5 without a "bull" so the 5 in the 2nd guess can't also be the "bull". Because 1 and 5 can't possibly be bulls the only number left is 7 so the code is _7_

Because of this we also know that in the first guess the 2 must be the "bull", as in the second spot only a 7 would be correct and the 1 is incorrect anyways -> the code is _72

"Cows"=right number at wrong position only appeared in the guesses 2 and 3 and we know it's neither the numbers 1 (because of guess 1), 7 (becuse it is a bull in 2) and 6 (because it is only in 3 and not both 2 and 3) -> the only number in guess 2 and 3 left is 5

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5 0
4 years ago
H(n)=-91\cdot\left(-\dfrac{1}{7}\right)^{\large{\,n-1}}h(n)=−91⋅(− 7 1 ​ ) n−1 h, left parenthesis, n, right parenthesis, equals
Kruka [31]

Given:

h(n)=-91\cdot\left(-\dfrac{1}{7}\right)^{\large{\,n-1}}

To find:

The recursive formula.

Solution:

We have,

h(n)=-91\cdot\left(-\dfrac{1}{7}\right)^{\large{\,n-1}}

It is in the form of explicate formula of a GP, .i.e., a_n=ar^{n-1}.

Here, a=-91 and r=-\dfrac{1}{7}.

The recursive formula of a GP is

a_n=a_{n-1}\times r

Using this the recursive formula for given problem is

h(n)=h(n-1)\times (-\dfrac{1}{7})

Therefore, the required recursive formula is h(n)=h(n-1)\times (-\dfrac{1}{7}).

8 0
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