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Yuliya22 [10]
3 years ago
9

What is the first term of the quotation of the following division problem?

Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

Answer:

I believe it's D.

Step-by-step explanation:

x^2 times x

Hope This Helps!       Have A Nice Day!!

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If the sum of a number and one is doubled​, the result is three less than the number. Find the number
goblinko [34]
Let the unknown number be x.

<span>sum of a number and one: x + 1
</span>
<span>sum of a number and one is doubled: 2(x + 1)
</span>
<span>three less than the number: x - 3

2(x + 1) = x - 3

2x + 2 = x - 3

x + 2 = -3

x = -5

The number is -5.
</span>
3 0
3 years ago
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Algebra
Tju [1.3M]

Answer:

nah its a.

Step-by-step explanation:

bakit?(#boyinthebrainly)

3 0
3 years ago
A car driving on a straight track accelerates at a rate of 3.2 m/s2 for 14 s. If the initial velocity of the car was 5.1 m/s, an
liraira [26]

Answer:

The data we have is:

The acceleration is 3.2 m/s^2 for 14 seconds

Initial velocity = 5.1 m/s

initial position = 0m

Then:

A(t) = 3.2m/s^2

To have the velocity, we integrate over time, and the constant of integration will be equal to the initial velocity.

V(t) = (3.2m/s^2)*t + 5.1 m/s

To have the position equation, we integrate again over time, and now the constant of integration will be the initial position (that is zero)

P(t) = (1/2)*(3.2 m/s^2)*t^2 + 5.1m/s*t

Now, the final position refers to the position when the car stops accelerating, this is at t = 14s.

P(14s) =   (1/2)*(3.2 m/s^2)*(14s)^2 + 5.1m/s*14s = 385m

So the final position is 385 meters ahead the initial position.

6 0
3 years ago
In a metal fabrication​ process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n
Leto [7]

Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, \bar{x} = 14.8 feet

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, σ = 0.65 feet

Degree of freedom = n - 1 = 15

95% Confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314  

14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)  

is the required confidence interval for the true mean length of rods.

3 0
3 years ago
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(2x)(x^2+4)... Find the value
mestny [16]
Hello, Here is the answer : 2x^3 + 8x .
5 0
3 years ago
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