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Yanka [14]
3 years ago
7

How to find the midpoint of a line segment with 2 given point?

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
7 0
If the 2 given points are endpoints, then we're in business.  The formula for the midpoint is M=( \frac{ x_{1}+ x_{2}  }{2}, \frac{ y_{1} + y_{2} }{2}).  If the endpoints of our segment are the coordinates (1,2) and (12,14), our formula would be filled in as follows: M=( \frac{1+12}{2}, \frac{2+14}{2}) which simplifies to (13/2, 8).  See?  It's pretty simple once you know how to do it.
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Find the product of 3 1/5 and 1 2/7. Express your answer in simplest form.
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Answer:

4\frac{1}{56}

Step-by-step explanation:

3\frac{1}{8} * 1 \frac{2}{7} = 4\frac{1}{56}

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3 years ago
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Svetradugi [14.3K]

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Step-by-step explanation:

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The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func
alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

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Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq  0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq  0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible  \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)

Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq  0\\-112 \geq  0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq  0\\80 \geq  0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq  0\\-112 \geq  0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution

Conclusion:

The domain of the function is the time in between 0 to 6 seconds

0 \leq  t \leq  6

The height will be positive in the above interval.

7 0
3 years ago
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umka2103 [35]

8(1/4)

=(8/1)

=(8)(1)/(1)(4)

=8/4

=2

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3 years ago
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