Step-by-step explanation:
11(2y+1)
hope it helps.....
Easy!!!!! its zero!!!!! LOL
Answer:
D 8√(10) ^3x
Step-by-step explanation:
We have
sqrt(10) ^ (3/4x)
We can rewrite the sqrt as ^1/2
10 ^ (1/2) ^ (3/4x)
We know that a^b^c = a^(b*c)
10 ^(1/2 *3/4x)
10 ^(3/8 x)
The numerator is the power
The denominator is the root
8√(10) ^3x
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)
your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°
-> insert those values, with c substituted with b+3 to remove c
c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE
DE=CE+3=36+3=39