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Hoochie [10]
2 years ago
5

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
3 0

Answer:

\frac{1}{a^{6} b^{4} }\\\frac{a^{6} }{b^{6} }\\ \frac{a^{6} }{b^{5} } \\\frac{b^{6} }{a^{6} }\\ a^{6} b^{3}

Step-by-step explanation:

Basically when a variable with a negative exponent, such as a^{-2}, you just take the reciprocal of it and then change the exponent sign, or in simple terms flip it. The reciprocal of a^{-2} and changing the exponent sign is is \frac{1}{a^{2} }.

To demonstrate let’s solve the first problem:

\frac{a^{-4}b^{-2}  }{a^{2} b^{2} }

Using what we just learned, we take the reciprocal and flip the sign of  a^{-4} and b^{-2}, which are \frac{1}{a^{4} } and \frac{1}{b^{2} } respectively.

Therefore the equation is now:

\frac{1}{a^{2}a^{4}b^{2}b^{2}    }

To simplify we add the exponents (only if they have the same base, or the same variable, in this case)

Therefore our answer is:

\frac{1}{a^{6}b^{4}  }

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Answer:

  1. Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
  2. Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E

Step-by-step explanation:

The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.

The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.

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<em>Additional comment</em>

The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.

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You know everything else except for t. Go back to your notes to search for t. Afterward, plug the value of t and everything else given above into the formula and calculate to find h.

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