Answer:
Step-by-step explanation:
1+2
+2v+4
9514 1404 393
Answer:
- Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
- Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E
Step-by-step explanation:
The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.
The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.
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<em>Additional comment</em>
The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.
The angle passes 90 degrees plus an additional 55 degrees
m
Answer:
61
Step-by-step explanation:
add the number of minutes for each day and then divide that number by the number of days


We are basically given most of what we need to calculate the height of the cannonball.
We use the formula h = –16t+ vt + s to find the height requested.
Let v = 160
Let s = 10
Let t = time in seconds
Was the value of t included? We need to know t to plug into our formula.
You know everything else except for t. Go back to your notes to search for t. Afterward, plug the value of t and everything else given above into the formula and calculate to find h.