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3241004551 [841]
3 years ago
13

What is the slope of the line y=8

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
There is no slope because the line is fully horizontal.
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Can anyone help me ???
tia_tia [17]

1.57, divide two times pi (3.14)

3 0
3 years ago
If the probability that 42 or fewer kids in a group of 57 like pizza is 79%, what is the probability that at least 43 kids in th
weqwewe [10]

Answer:

Step-by-step explanation:

43

7 0
3 years ago
Read 2 more answers
the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
Leo needs 10 red roses and 1515 pink daisies for every 5 bouquets he makes for a flower shop. Drag red roses and pink daisies in
Marina CMI [18]
2 red roses per bouquet. 3 pink daisies are needed.
2•3=6
3•3=9
9+6=15
he needs 6 roses and 9 daisies.
3 0
3 years ago
Read 2 more answers
Is the given function phi(x) = x^2 - x^-1 an explicit solution to the linear equation d^2y/dx^2 - 2/x^2 y = 0? Circle your answe
mart [117]

Answer:

Yes

Step-by-step explanation:

We are given that a function \phi(x)=x^2-x^{-1}

We have to find that given function is an explicit solution to the linear equation

\frac{d^2y}{dx^2}-\frac{2}{x^2}y=0

If given function is an explicit solution of given linear equation then it satisfied the given differential equation

Differentiate w.r.t x

Then we get \phi'(x)=2x+x^{-2}

Again differentiate w.r.t x

Then we get

\phi''(x)=2-\frac{2}{x^3}

Substitute all values in the given differential equation

2-\frac{2}{x^3}-\frac{2}{x^2}(x^2-x^{-1})

=2-\frac{2}{x^3}-2+\frac{2}{x^3}=0

Hence, given function is an explicit solution of given differential equation.

Therefore, answer is yes.

3 0
3 years ago
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