Question

Vector vector A has a magnitude A and is directed at an angle theta measured with respect to the positive x-axis. What is the magnitude of vector A sub x, the x-component of vector A?

Answer 1

Answer:$A_x$ = Acos$\theta$

Explanation:

A vector in this situation have two components

1) The X-component

2) The Y-component

So as we put $cos\theta$ with the x-axis while $sin\theta$ with the y- axis and this case our answer should be

$A_x$ = Acos$\theta$

I hope this will answer your question,

An image is also provided please have a look at that.

Thank you.

Answer 2

Answer: Ax = Acos(theta)

Therefore, the x component of A: Ax = Acos(theta)

Explanation:

The attached image is a pictorial representation of the question:

From the attached image,

Cos(theta) = adjacent/hypothenus

Cos(theta) = Ax/A

Making Ax the subject of formula,

Ax = Acos(theta)

Therefore, the x component of A: Ax = Acos(theta)