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I am Lyosha [343]
2 years ago
15

if a copper coin with a volume of exactly 50 cubic cm is dropped into the volume of water 4cubic cm,how much water will be overf

lown (water is half way of the can)
Physics
1 answer:
Alenkinab [10]2 years ago
7 0

Answer:

50 cubic cm

Explanation:

As the water displaces 50 cubic centimeters the amount of water that must leave the container for it to be able to be dropped into it is also 50 cubic as the water which was in its place must have gone somewhere.

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A bucket of water of mass 14.0 kg is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.260
ruslelena [56]

Answer:

The tension in the rope is 41.38 N.

Explanation:

Given that,

Mass of bucket of water = 14.0 kg

Diameter of cylinder = 0.260 m

Mass of cylinder = 12.1 kg

Distance = 10.7 m

Suppose we need to find that,

What is the tension in the rope while the bucket is falling

We need to calculate the acceleration

Using relation of torque

\tau=F\times r

I\times\alpha=F\times r

Where, I = moment of inertia

\alpha = angular acceleration

\dfrac{Mr^2}{2}\times\dfrac{a}{r}=F\times r

F=\dfrac{M}{2}a...(I)

Here, F = tension

The force is

F=m(g-a)...(II)

Where, F = tension

a = acceleration

From equation (I) and (II)

\dfrac{M}{2}a=m(g-a)

a=\dfrac{g}{1+\dfrac{M}{2m}}

Put the value into the formula

a=\dfrac{9.8}{1+\dfrac{12.1}{2\times14.0}}

a=6.84\ m/s^2

We need to calculate the tension in the rope

Using equation (I)

F=\dfrac{M}{2}a

Put the value into the formula

F=\dfrac{12.1}{2}\times6.84

F=41.38\ N

Hence, The tension in the rope is 41.38 N.

6 0
3 years ago
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