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masya89 [10]
4 years ago
14

A quantity of 14.1 cm^3 of water at 8.4°C is placed in a freezer compartment and allowed to freeze to solid ice at -7.2°C. How m

any joules of energy must be withdrawn from the water by the refrigerator?
Physics
1 answer:
serious [3.7K]4 years ago
3 0

Answer:920.31 J

Explanation:

Given

Volume of water (V)=14.1 cm^3

mass(m)=\rho \times V=1000\times 14.1\times 10^{-6}=14.1 gm

Temperature =8.4^{\circ} C

Final Temperature =-7.2 ^{\circ}C

specific heat of water(c)=4.184 J/g-^{\circ}C

Therefore heat required to removed is

Q=mc(\Delta T)

Q=14.1\times 4.184\times (8.4-(-7.2))

Q=920.31 J

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Answer:

Explanation:

Given that,

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Then,

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P.D_total = 6V.

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R = 15,000Ω

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Using ohms law

V = IR

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I = 0.4 × 10^-3 A

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3 years ago
Which one of the following types of training involves 10 to 30 minutes of high-intensity exercise?
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Correct answer choice is:



C. Medium range



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The blades in a blender rotate at a rate of 7700 rpm. when the motor is turned off during operation, the blades slow to rest in
Tpy6a [65]

Angular acceleration = (change in angular speed) / (time for the change)

Change in angular speed = (speed at the end) - (speed at the beginning)

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Change in angular speed = -7700 rpm

Angular acceleration = (-7700 rpm) / (2.5 sec)

<em>Angular acceleration = -3,080 rev per minute / sec</em>

That's a perfectly good and true answer to the question, but the units are ugly.  We really need to fix the units, and convert them into something prettier before we hand in this assignment.

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