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masya89 [10]
4 years ago
14

A quantity of 14.1 cm^3 of water at 8.4°C is placed in a freezer compartment and allowed to freeze to solid ice at -7.2°C. How m

any joules of energy must be withdrawn from the water by the refrigerator?
Physics
1 answer:
serious [3.7K]4 years ago
3 0

Answer:920.31 J

Explanation:

Given

Volume of water (V)=14.1 cm^3

mass(m)=\rho \times V=1000\times 14.1\times 10^{-6}=14.1 gm

Temperature =8.4^{\circ} C

Final Temperature =-7.2 ^{\circ}C

specific heat of water(c)=4.184 J/g-^{\circ}C

Therefore heat required to removed is

Q=mc(\Delta T)

Q=14.1\times 4.184\times (8.4-(-7.2))

Q=920.31 J

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