Question

A quantity of 14.1 cm^3 of water at 8.4°C is placed in a freezer compartment and allowed to freeze to solid ice at -7.2°C. How many joules of energy must be withdrawn from the water by the refrigerator?

Answer 1

Answer:920.31 J

Explanation:

Given

Volume of water (V)$=14.1 cm^3$

mass(m)$=\rho \times V=1000\times 14.1\times 10^{-6}=14.1 gm$

Temperature $=8.4^{\circ} C$

Final Temperature $=-7.2 ^{\circ}C$

specific heat of water(c)$=4.184 J/g-^{\circ}C$

Therefore heat required to removed is

$Q=mc(\Delta T)$

$Q=14.1\times 4.184\times (8.4-(-7.2))$

$Q=920.31 J$