3 years ago

Number of minutes 1 2 3 4 5 6 7 8 9 10

Mathematics

1 answer:

umka21 [38]3 years ago

4 0

Answer: please find the attached file for the graph.

Step-by-step explanation:

Number of minutes 1 2 3 4 5 6 7 8 9 10Number of trainees 2 3 5 10 15 30 25 15 10 5

Given that data set above, the time in minutes will be on the x axis while the number of trainees will be in the y axis.

In bar chart, the bars will not touch each other.

Please find the attached file for the solution and figure

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rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$