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3 years ago

9

-5x-16=9x+x-1 Solve the equation.

2 answers:

nadezda [96]3 years ago

7 0

Answer:

x= -1

Step-by-step explanation:

-5x-16=9x+x-1

-5x-9x-x=16-1

-15x=15

x= -1

Serggg [28]3 years ago

4 0

Answer:

x=-1

Step-by-step explanation:

15x=-15

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Step-by-step explanation:

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3 years ago

S=L (1 - r), for r

maria [59]

OK. Then let's solve for ' r '. That means you have to come up with an equation that says   r = everything else.

Step #1:
Write the equation you're given:   <span>S = L (1 - r)

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3 years ago

What is a square root of (a-b)^2

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Hello,

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2 years ago

Write the decimal expansion for <br> .

Slav-nsk [51]

Answer:

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Step-by-step explanation:

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2 years ago

Find the range of y = 3/2 cos 4x - 1

motikmotik

Answer:

B. $-2\frac{1}{2} \leq y \leq \frac{1}{2}$

Step-by-step explanation:

The given trigonometric function is

$f(x)=\frac{3}{2}cos4x-1$ .

The amplitude of this function is $\frac{3}{2}$ , so under normal circumstances the range is supposed to be

$-\frac{3}{2} \leq y \leq \frac{3}{2}$

But the $-1$ is a downward vertical shift.

Therefore the normal boundaries of the range will shift down one unit to give the range of the transformed function.

We subtract 1 from the lower boundary to get $-\frac{3}{2}-1=-2\frac{1}{2}$

We also subtract 1 from the upper boundary to get $-frac{3}{2}-1=\frac{1}{2}$

Hence the range is

$-2\frac{1}{2} \leq y \leq \frac{1}{2}$

Also see graph

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3 years ago