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3 years ago

A lunch box costs $4.50 plus sales tax. After sales tax, the lunch box is $4.86. What is the sales tax rate?

1 answer:

3 0

8 percent (C)

To find 1% you divide 4.50 by 100, which is 0.045.

Then you have to find what is added on.
4.86-4.50 is .36

Now you divide .36 by 0.045. An easier way to do this is 360 divided by 45. This equals 8.

Hope this helped

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A high rise apartment building has 15 floors with 26 apartments on each floor.There are 3 kinds of apartments in the building: 1

konstantin123 [22]

Answer:

The number of each kind of apartment in the building is 130 .

Step-by-step explanation:

Given as :

The total number of floor in a building = 15

The number of apartment on each floor = 26

So, The total number of apartment = 26 × 15 = 390

The number of kinds of apartment in the building is 3 , i.e 1-bedroom , 2-bedroom , 3-bedroom

Let The number of each kind of apartment in building = x

So, According to question

The number of each kind of building = $\dfrac{\textrm Total number of apartment }{number of kinds of apartment}$

or, x = $\frac{390}{3}$

∴ x = 130

Hence The number of each kind of apartment in the building is 130 . Answer

3 0

3 years ago

50 POINTS for both questions

love history [14]

Answer:

3. i think 15.5

4. 140*

Step-by-step explanation:

in number 4, d is a vertical angle to the angle measured at 140.

in number 3, QV=SV, so 17=4x-1 18=4x 18/4=x x=4.5

and TS=TQ, so 3(x) + 2 = 3(4.5) + 2 = 13.5 + 2 = 15.5 =TQ

6 0

3 years ago

Read 2 more answers

Pleaseeee helpp❗️❗️❗️❗️

liq [111]

4 is b( do on your calculator)
5 is b(do on your calculator)
6 is a

4 0

3 years ago

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

3 years ago

Helppp meee plssss

Volgvan

Answer:

Cost of fish = Php. 60, amount of fish = x kg
Cost of chicken = Php. 120, amount of chicken = y kg
Budget = at most Php. 1200

a) Required inequality (not a system as only one condition is given):

60x + 120y ≤ 1200

Simplified:

x + 2y ≤ 20

The graph is attached

b) Verify ordered pair (10, 7):

10 + 2*7 ≤ 20
24 ≤ 20

False inequality, so this pair is out of solution set

8 0

3 years ago