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marishachu [46]
3 years ago
15

Find the value of x.

Mathematics
2 answers:
bonufazy [111]3 years ago
6 0

Answer:

61

Step-by-step explanation:

avanturin [10]3 years ago
6 0
The answer is 61 . I know that because the value of x is Däk Vüha

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I need help, someone help me, please
lara [203]

Answer:

(a): 46 degrees

(b): 63 degrees

(c): 27 degrees

(d): 60 degrees

Step-by-step explanation:

6 0
2 years ago
2
KIM [24]

Answer:

answer is in an image here

imageshare.best/image.php?id=JS9NDO

Explanation:

copy n paste in browser

not a bot btw

8 0
2 years ago
Read 2 more answers
How do you divide 75 into 1000
Maksim231197 [3]
The answer is going to be a fraction...which is 75/1000, otherwise known as 1/40
3 0
3 years ago
PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM
Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = \sqrt{40^{2} + 9^{2} }

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

b = 5 \sqrt{33}

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

1369 = 400 + b^{2}

b^{2} = 1369 - 400

b^{2} = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0
2 years ago
Find the derivative of f(x) = 2x^2 - 4x +3
ivolga24 [154]

Explanation

2x^2-4x+3

When taking derivatives of polynomials, we primarily make use of the power rule.

Power rule.

\begin{gathered} f(x)=x^n \\ \text{then} \\ f^{\prime}(x)=nx^{n-1} \end{gathered}

also, the derivate of a sum is the sum of the derivates

hence

\begin{gathered} g(x)=f(x)+h(x)+\ldots z(x) \\ g^{\prime}(x)=f^{\prime}(x)+h^{\prime}(x)+\ldots.z^{\prime}(x) \end{gathered}

Step 1

apply:

\begin{gathered} f(x)=2x^2-4x+3 \\ f^{\prime}(x)=2\cdot2x^{2-1}-4(1)x^{1-1}+ \\ f^{\prime}(x)=4x^{}-4(1)x^0+3^0 \\ f^{\prime}(x)=4x^{}-4(1)(1) \\ f^{\prime}(x)=4z-4 \end{gathered}

therefore, the answer is

8 0
1 year ago
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