The probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.
<u>Step-by-step explanation:</u>
- There are 1 red ball and 4 white balls in a box.
- The total number of balls in the box = 1 red + 4 white = 5 balls.
The two balls are drawn without replacement.
<u>Drawing the first ball :</u>
The first draw should be a red ball.
The probability to get a red ball = No.of red balls / Total balls in the box.
We know that, No. of red balls is 1 and total balls in the box is 5.
P(red ball) = 1/5
<u>Drawing the second ball :</u>
The second draw should be a white ball.
The probability to get white ball = No.of white balls / Total balls in the box.
We know that,
No. of white balls is 4.
The total balls in the box after the first draw will be 4 balls.
P(white ball) = 4/4
The probability of getting a red ball on the first drawn and a white ball on the second draw = P(red ball) × P(white ball)
⇒ (1/5) × (4/4)
⇒ 4/20
⇒ 1/5
Therefore, the probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.
Answer:
n = 6.39
Explanation:
2.3 + 4.09 = n
6.39 = n
Swap the sides of the equation
n = 6.39
7/10=70/100=70%, so the answer is seventy-percent.
Going from the left to the right. 9, 4, 13, 15, 12, 6, 11. The total cost is the sum of these, or $70,000.
Subtract 10 and divide by 7
