I assume there are some plus signs that aren't rendering for some reason, so that the plane should be

.
You're minimizing

subject to the constraint

. Note that

and

attain their extrema at the same values of

, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is

Take your partial derivatives and set them equal to 0:

Adding the first three equations together yields

and plugging this into the first three equations, you find a critical point at

.
The squared distance is then

, which means the shortest distance must be

.
Answer:
The slope is -2/3.
Step-by-step explanation
Let m represent the slope.
m= rise/run= y2-y1/x2-x1
-1 - (-3)/0-3
2/-3
-2/3
$300
3%=.03 of something
Find .03 of 10000
10000x.03=$300
6.5 + 7.6
8.4 + 5.7
ur welcome
Answer:
here is what i found also you could of looked it up
Step-by-step explanation:
(x,y)→(x+4,y)