Answer:
set y=0 in one of the equations and then in the other one set x=0
Step-by-step explanation:
below is how you do it
y=5x-5 y=3x+3
0=5x-5 y=3(0) +3
5=5x y=3
1=x
So if she picked 32 apples on Tuesday, and she picked 15 more apples than on Monday, then she picked 17 apple on Monday, because 17+15=32. A=17
You can't change the sum by changing the grouping. Any way you cut it, you will always get 226, as you only have addition operations, and the commutative property [a+(b+c)=(a+b)+c] means that the sum will always be the same.
a) (0.17 ac)×(126 min/ac) = 21.42 min
b) I can mow 1/126 ac/min; you can mow 1/117 ac/min. Together, we can mow at a rate that is the sum of these:
... (1/126 + 1/117) ac/min = (117 + 126)/(126×117) = 243/14,742 ac/min
Then it will take 14,742/243 min/ac × 0.17 ac/lawn ≈ 10.31 min/lawn
